Let (Wt)t≥0 be a standard Brownian motion, and let Xt be defined by:
dXt=−aXtdt+σdWt,XDefine the stopping time:
T:=inf{t≥0∣Xt∈/(b,c)}.We admit that P(T<∞)=1.
Question: Determine the probability that Xt exits the interval from the left, i.e.:
P(XT=b).